Solve 2sin(θ) = √3 for 0° ≤ θ < 360°.

Start with the equation:
2sin(θ) = √3

Divide both sides by 2:
sin(θ) = √3/2

The reference angle whose sine is √3/2 is 60° because:
sin(60°) = √3/2

Sine is positive in Quadrants I and II.

In Quadrant I:
θ = 60°

In Quadrant II:
θ = 180° - 60°
θ = 120°

Both angles are in the required interval 0° ≤ θ &lt; 360°.

Therefore, the solutions are θ = 60° and θ = 120°.