A class has 12 boys and 18 girls. If two students are selected at random without replacement, what is the probability that both are girls?
Solution
Problem
A class has 12 boys and 18 girls. If two students are selected at random without replacement, what is the probability that both are girls?
Step 1: Find the total number of students.
12 + 18 = 30
There are 30 students total.
Step 2: Find the probability that the first student selected is a girl.
There are 18 girls among 30 students:
P(first girl) = 18/30
Step 3: Find the probability that the second student is a girl given that the first was a girl.
Because the selection is without replacement, there are now 17 girls remaining among 29 students.
P(second girl | first girl) = 17/29
Step 4: Multiply the probabilities.
P(both girls) = (18/30)(17/29)
Step 5: Simplify.
P(both girls) = 306/870
P(both girls) = 51/145
As a decimal:
51/145 โ 0.352
Therefore, the probability that both selected students are girls is 51/145, or approximately 0.352.
Result
51/145 โ 0.352