Power when 600 J of work is done in 12 s
Solution
Problem
Power when 600 J of work is done in 12 s
Assumptions: average power is requested over the full time interval.
Use P = W/t.
P = (600 J)/(12 s)
P = 50 J/s
Since 1 W = 1 J/s, the average power is 50 W.
Result
50 W