How many moles of gas are in 2.50 L at 1.00 atm and 298 K? Use R = 0.0821 Latm/(molK).

Solution

Chemistry · Medium

Problem

How many moles of gas are in 2.50 L at 1.00 atm and 298 K? Use R = 0.0821 L*atm/(mol*K).

Use the ideal gas law PV = nRT.
n = PV / RT
n = (1.00 atm)(2.50 L) / [(0.0821 L*atm/(mol*K))(298 K)]
n = 0.102 mol.

0.102 mol