What volume of a 2.00 M stock solution is needed to make 250.0 mL of a 0.150 M solution?

Solution

Chemistry · Easy

Problem

What volume of a 2.00 M stock solution is needed to make 250.0 mL of a 0.150 M solution?

Use the dilution relationship M1V1 = M2V2.
(2.00 M)(V1) = (0.150 M)(250.0 mL)
V1 = (0.150 M * 250.0 mL) / 2.00 M
V1 = 18.75 mL
With 3 significant figures, V1 = 18.8 mL.

Result

18.8 mL